Einzelnen Beitrag anzeigen
  #22  
Alt 11.01.19, 00:56
Benutzerbild von TomS
TomS TomS ist offline
Singularität
 
Registriert seit: 04.10.2014
Beitr?ge: 3.124
Standard AW: Was ist eine Observable?

Zitat:
Zitat von Bernhard Beitrag anzeigen
Siehe dazu: https://de.wikipedia.org/wiki/Hermit...scher_Operator . Der erste Satz dieses Abschnittes trifft es doch ganz gut.
Der Artikel ist m.E. gruselig!

Stattdessen:

https://en.m.wikipedia.org/wiki/Self-adjoint_operator

Subtleties of the unbounded case
In many applications, we are led to consider operators that are unbounded; examples include the position, momentum, and Hamiltonian operators in quantum mechanics, as well as many differential operators. In the unbounded case, there are a number of subtle technical issues that have to be dealt with. In particular, there is a crucial distinction between operators that are merely symmetric (defined in this section) and those that are self-adjoint (defined in the next section). In the case of differential operators defined on bounded domains, these technical issues have to do with making an appropriate choice of boundary conditions ...

In the physics literature, the term Hermitian is used in place of the term symmetric. It should be noted, however, that the physics literature generally glosses over the distinction between operators that are merely symmetric and operators that are actually self-adjoint ...

Although the notion of a symmetric operator is easy to understand, it is not the "right" notion in the unbounded case. Specifically, the spectral theorem applies only to operators that are self-adjoint and not to operators that are merely symmetric. In particular, although the eigenvalues of a symmetric operator are necessarily real, a symmetric operator need not have any eigenvectors, let alone an orthonormal basis of them.
__________________
Niels Bohr brainwashed a whole generation of theorists into thinking that the job (interpreting quantum theory) was done 50 years ago.
Mit Zitat antworten